| Equations balanced on the previous day | Equations balanced on the next day |
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NaOH + HNO3 = NaNO3 + H2O
CaO + HNO3 = Ca(NO3)2 + H2O =>
CaO + 2 HNO3 = Ca(NO3)2 + H2O
HCl + H2O = HO + ClH2 =>
HCl + H2O = HO + ClH2
HNO3 + H2S = NO + S + H2O =>
2 HNO3 + 3 H2S = 2 NO + 3 S + 4 H2O
HBr + Ca(OH)2 = H2O + CaBr2 =>
2 HBr + Ca(OH)2 = 2 H2O + CaBr2
CH4 + O2 = C + H2O =>
CH4 + O2 = C + 2 H2O
Na2CO3 + Mg(NO3)2 = MgCO3 + NaNO3 =>
Na2CO3 + Mg(NO3)2 = MgCO3 + 2 NaNO3
H3PO4 + MgCl2 + NH4OH = NH4MgPO4 + HCl + H2O =>
H3PO4 + MgCl2 + NH4OH = NH4MgPO4 + 2 HCl + H2O
C2H6O + Cr2O7{2-} + H{+} = C2H4O + H2O + Cr{3+} =>
3 C2H6O + Cr2O7{2-} + 8 H{+} = 3 C2H4O + 7 H2O + 2 Cr{3+}
KBr + KMnO4 + H2SO4 = Br2 + MnSO4 + KSO4 + H2O =>
2 KBr + KMnO4 + 4 H2SO4 = Br2 + MnSO4 + 3 KSO4 + 4 H2O
MgCO3 + H3PO4 = Mg3(PO4)2 + CO2 + H2O =>
3 MgCO3 + 2 H3PO4 = Mg3(PO4)2 + 3 CO2 + 3 H2O
Sn + Fe(NO3)3 = Sn(NO3)2 + Fe =>
3 Sn + 2 Fe(NO3)3 = 3 Sn(NO3)2 + 2 Fe
(NH4)3PO4 + NaOH = Na3PO4 + NH3 + H2O =>
(NH4)3PO4 + 3 NaOH = Na3PO4 + 3 NH3 + 3 H2O
NaOH + H2S = H2O + NaHS =>
NaOH + H2S = H2O + NaHS
Pb(OH) + HNo3 = PbNo3 + H2O =>
Pb(OH) + HNo3 = PbNo3 + H2O
H3PO4 + Ba(OH)2 = H2O + Ba3(PO4)2 =>
2 H3PO4 + 3 Ba(OH)2 = 6 H2O + Ba3(PO4)2
LiHCO3 + H2SO4 = Li2SO4 + H2O + CO2 =>
2 LiHCO3 + H2SO4 = Li2SO4 + 2 H2O + 2 CO2
C2H6S + O2 = CO2 + H2O + SO2 =>
2 C2H6S + 9 O2 = 4 CO2 + 6 H2O + 2 SO2
Sn + MgSO4 = SnSO4 + Mg =>
Sn + MgSO4 = SnSO4 + Mg
Sn + MgSO4 = Sn(SO4)4 + Mg =>
Sn + 4 MgSO4 = Sn(SO4)4 + 4 Mg
C4H10O + O2 = CO2 + H2O =>
C4H10O + 6 O2 = 4 CO2 + 5 H2O
HNO3 + MgCO3 = H2O + CO2 + Mg(NO3)2 =>
2 HNO3 + MgCO3 = H2O + CO2 + Mg(NO3)2
Bi{3+}(aq) + Fe{3+}(aq) + H2O = BiO3{-} + Fe{2+} + H{+}(aq) =>
Bi{3+}(aq) + 2 Fe{3+}(aq) + 3 H2O = BiO3{-} + 2 Fe{2+} + 6 H{+}(aq)
I{-} + Cr2O7{2-} + H{+} = Cr{3+} + I2 + H2O =>
6 I{-} + Cr2O7{2-} + 14 H{+} = 2 Cr{3+} + 3 I2 + 7 H2O
C2H6 + O2 = CO2 + H2O =>
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O
Ba(NO3)2 + NH4CO3 = Ba(CO3)2 + NH4NO3 =>
Ba(NO3)2 + 2 NH4CO3 = Ba(CO3)2 + 2 NH4NO3
HSO4 + NaOH = H2O + NaSO4 =>
HSO4 + NaOH = H2O + NaSO4
PbCrO4 + HCl = PbCl2 + CrCl3 + Cl2 + H2O =>
2 PbCrO4 + 16 HCl = 2 PbCl2 + 2 CrCl3 + 3 Cl2 + 8 H2O
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| Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 08/30/12
Equations balanced on 09/29/11
Deje su comentario acerca de su experiencia utlizando el balanceador de ecuaciones quìmicas.
