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Chemical Equations Balanced on 12/30/20

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Balance equation of any chemical reaction online for free
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CaCl2 + Na3PO4 = Ca3(PO4)2 + NaCl =>
3 CaCl2 + 2 Na3PO4 = Ca3(PO4)2 + 6 NaCl

HCl + KOH = KCl + H2O =>
HCl + KOH = KCl + H2O

Al + H2SO4 = Al2(SO4)3 + H2 =>
2 Al + 3 H2SO4 = Al2(SO4)3 + 3 H2

CaCl2 + Na3PO4 = Ca3(PO4)2 + NaCl =>
3 CaCl2 + 2 Na3PO4 = Ca3(PO4)2 + 6 NaCl

Cr + Cl2 = CrCl3 =>
2 Cr + 3 Cl2 = 2 CrCl3

PCl3 + H2O = H3PO3 + HCl =>
PCl3 + 3 H2O = H3PO3 + 3 HCl

(NH3) + O2 = NO + H2O =>
4(NH3) + 5 O2 = 4 NO + 6 H2O

CaCl2 + Na2CO3 = CaCO3 + NaCl =>
CaCl2 + Na2CO3 = CaCO3 + 2 NaCl

CH4 + O2 = CO2 + H2O =>
CH4 + 2 O2 = CO2 + 2 H2O

Fe(NO3)3 + KOH = Fe(OH)3 + K(NO3) =>
Fe(NO3)3 + 3 KOH = Fe(OH)3 + 3 K(NO3)

Zn + Pb(NO3)2 = Zn(NO3)2 + Pb =>
Zn + Pb(NO3)2 = Zn(NO3)2 + Pb

P4 + HNO3 = H3PO4 + NO2 + H2O =>
P4 + 20 HNO3 = 4 H3PO4 + 20 NO2 + 4 H2O

P4 + HNO3 = H3PO4 + NO2 + H2O =>
P4 + 20 HNO3 = 4 H3PO4 + 20 NO2 + 4 H2O

Pb(NO3)2 + BaCl2 = PbCl2 + Ba(NO3)2 =>
Pb(NO3)2 + BaCl2 = PbCl2 + Ba(NO3)2

KMnO4 + HCl = KCl + MnCl2 + H2O + Cl2 =>
2 KMnO4 + 16 HCl = 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2

CH4 + O2 = CO2 + H2O =>
CH4 + 2 O2 = CO2 + 2 H2O

ZnCl2 + H2S = ZnS + HCl =>
ZnCl2 + H2S = ZnS + 2 HCl

CH3COOH + O2 = CO2 + H2O =>
CH3COOH + 2 O2 = 2 CO2 + 2 H2O

CH4 + O2 = CO + H2O =>
2 CH4 + 3 O2 = 2 CO + 4 H2O

AgNO3 + Na2CrO4 = Ag2CrO4 + NaNO3 =>
2 AgNO3 + Na2CrO4 = Ag2CrO4 + 2 NaNO3

KMnO4 + HCl = KCl + MnCl2 + H2O + Cl2 =>
2 KMnO4 + 16 HCl = 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2

CaCl2 + Na3PO4 = Ca3(PO4)2 + NaCl =>
3 CaCl2 + 2 Na3PO4 = Ca3(PO4)2 + 6 NaCl

K + H2O = KOH + H2 =>
2 K + 2 H2O = 2 KOH + H2

AlBr3 + Cl2 = AlCl3 + Br2 =>
2 AlBr3 + 3 Cl2 = 2 AlCl3 + 3 Br2

Ag + NaCl = AgCl + Na =>
Ag + NaCl = AgCl + Na

CrI3 + KOH + Cl2 = K2CrO4 + KIO4 + KCl + H2O =>
2 CrI3 + 64 KOH + 27 Cl2 = 2 K2CrO4 + 6 KIO4 + 54 KCl + 32 H2O

NaIO3 + Na2SO3 + NaHSO3 = I2 + Na2SO4 + H2O =>
2 NaIO3 + 3 Na2SO3 + 2 NaHSO3 = I2 + 5 Na2SO4 + H2O

PbCl2 + AgNO3 = AgCl + Pb(NO3)2 =>
PbCl2 + 2 AgNO3 = 2 AgCl + Pb(NO3)2

N2 + H2 = NH3 =>
N2 + 3 H2 = 2 NH3

(NH4)3PO4 + Zn(NO3)2 = NH4NO3 + Zn3(PO4)2 =>
2(NH4)3PO4 + 3 Zn(NO3)2 = 6 NH4NO3 + Zn3(PO4)2

KOH + H3PO4 = K3PO4 + H2O =>
3 KOH + H3PO4 = K3PO4 + 3 H2O

CrI3 + K(OH) + S = K(IO4) + K2(Cr2O7) + K2S + H2O =>
2 CrI3 + 62 K(OH) + 27 S = 6 K(IO4) + K2(Cr2O7) + 27 K2S + 31 H2O

CH4(g) + Cl2(g) = CCl4(l) + HCl(g) =>
CH4(g) + 4 Cl2(g) = CCl4(l) + 4 HCl(g)

LiOH + VCl3 = LiCl + V(OH)3 =>
3 LiOH + VCl3 = 3 LiCl + V(OH)3

CaCl2 + Na2CO3 = CaCO3 + NaCl =>
CaCl2 + Na2CO3 = CaCO3 + 2 NaCl

CaCl2 + Na2CO3 = CaCO3 + NaCl =>
CaCl2 + Na2CO3 = CaCO3 + 2 NaCl

NaIO3 + Na2SO3 + H2O = I2 + Na2SO4 + NaOH =>
2 NaIO3 + 5 Na2SO3 + H2O = I2 + 5 Na2SO4 + 2 NaOH

CaCl2 + Na2CO3 = CaCO3 + NaCl =>
CaCl2 + Na2CO3 = CaCO3 + 2 NaCl

CrI3 + K(OH) + S = K(IO4) + K2(Cr2O7) + K2S + H2O =>
2 CrI3 + 62 K(OH) + 27 S = 6 K(IO4) + K2(Cr2O7) + 27 K2S + 31 H2O

LiOH + Mg = Li + O2 + H2Mg =>
2 LiOH + Mg = 2 Li + O2 + H2Mg

NH2OH + HNO3 = NH3OH + NO3 =>
NH2OH + HNO3 = NH3OH + NO3

CaCl2 + K3PO4 = Ca3(PO4)2 + KCl =>
3 CaCl2 + 2 K3PO4 = Ca3(PO4)2 + 6 KCl

Na + Cl2 = NaCl =>
2 Na + Cl2 = 2 NaCl

Mn(SO4) + PbO2 + HNO3 = Pb(SO4) + Pb(NO3)2 + HMnO4 + H2O =>
2 Mn(SO4) + 5 PbO2 + 6 HNO3 = 2 Pb(SO4) + 3 Pb(NO3)2 + 2 HMnO4 + 2 H2O

K[Cr(C2O4)2(H2O)(NH4OH)] + HCl = K[Cr(C2O4)2(H2O)2] + NH4Cl =>
K[Cr(C2O4)2(H2O)(NH4OH)] + HCl = K[Cr(C2O4)2(H2O)2] + NH4Cl

Cl2 + KOH = KCl + KClO3 + H20 =>
30 Cl2 + 60 KOH = 40 KCl + 20 KClO3 + 3 H20

NO2{-} + Al + OH{-} + H2O = NH3 + AlO2{-} =>
NO2{-} + 2 Al + OH{-} + H2O = NH3 + 2 AlO2{-}

C4H3N2NaO3 + HCl = NaCl + C4H4N2O3 =>
C4H3N2NaO3 + HCl = NaCl + C4H4N2O3

Al2(SO4)3 + Ca(OH)2 = Al(OH)3 + CaSO4 =>
Al2(SO4)3 + 3 Ca(OH)2 = 2 Al(OH)3 + 3 CaSO4

Al2(SO4)3 + Ca(OH)2 = Al(OH)3 + CaSO4 =>
Al2(SO4)3 + 3 Ca(OH)2 = 2 Al(OH)3 + 3 CaSO4

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Balance equation of any chemical reaction online for free
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Equations balanced on 12/30/19
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