Ecuaciones balanceadas el día anterior |
Cu + Ag2SO4 = CuSO4 + 2 Ag
CoOHCl + NH4OH = [Co(NH3)6](OH)2 + NH4Cl + H2O =>
CoOHCl + 7 NH4OH = [Co(NH3)6](OH)2 + NH4Cl + 6 H2O
Cu(OH)2CuCO3(s) = Cu2O(s) + CO2 + H2O + O2 =>
2 Cu(OH)2CuCO3(s) = 2 Cu2O(s) + 2 CO2 + 2 H2O + O2
Cr2(SO4)2 + Br2 + NaOH = Na2SO4 + NaCrO4 + NaBr + H2O =>
Cr2(SO4)2 + 5 Br2 + 16 NaOH = 2 Na2SO4 + 2 NaCrO4 + 10 NaBr + 8 H2O
CuI2 + HNO3 = CuNO3 + I2 + NO2 + H2O =>
CuI2 + 2 HNO3 = CuNO3 + I2 + NO2 + H2O
Cl{-} + H3O{+} + Cr2O7{-2} = H2O + Cl2 + Cr{+3} =>
6 Cl{-} + 14 H3O{+} + Cr2O7{-2} = 21 H2O + 3 Cl2 + 2 Cr{+3}
Cu(OH)2 + C2H5OH = CH3CHO + Cu + H2O =>
Cu(OH)2 + C2H5OH = CH3CHO + Cu + 2 H2O
C7H6O3 + C4H6O3 = C9H8O4 = CH3COOH =>
11 C7H6O3 + C4H6O3 = 9 C9H8O4
CuI2 + Cl = CuCl2 + I2 =>
CuI2 + 2 Cl = CuCl2 + I2
Ca3(PO4)2 + Ag2SO4 = Ca(SO4) + Ag3(PO4) =>
Ca3(PO4)2 + 3 Ag2SO4 = 3 Ca(SO4) + 2 Ag3(PO4)
Na2[Be(OH)4] + HNO3 = Be(NO3)2 + NaNO3 + H2O =>
Na2[Be(OH)4] + 4 HNO3 = Be(NO3)2 + 2 NaNO3 + 4 H2O
K2MnO4 + FeCl2 + HCl = MnCl2 + FeCl3 + KCl + H2O =>
K2MnO4 + 4 FeCl2 + 8 HCl = MnCl2 + 4 FeCl3 + 2 KCl + 4 H2O
SrCO3 + Nb2O5 = Sr2Nb2O7 + CO2 =>
2 SrCO3 + Nb2O5 = Sr2Nb2O7 + 2 CO2
AgOH + NaOH = AgNa + H2O2 =>
AgOH + NaOH = AgNa + H2O2
Fe(C2H3O2)2 + KOH = Fe(OH)2 + KC2H3O2 =>
Fe(C2H3O2)2 + 2 KOH = Fe(OH)2 + 2 KC2H3O2
Sr + HCl = SrCl2 + H =>
Sr + 2 HCl = SrCl2 + 2 H
CuSO4 + H2O2 = CuO2 + H2SO4 =>
CuSO4 + H2O2 = CuO2 + H2SO4
CH3CH2OH + KMnO4 = CH3COOH + H2O + MnO2 + KOH =>
3 CH3CH2OH + 4 KMnO4 = 3 CH3COOH + H2O + 4 MnO2 + 4 KOH
Cu(OH)2 + H2SO4 = CuSO4 + H2O =>
Cu(OH)2 + H2SO4 = CuSO4 + 2 H2O
Cu + Ca3(PO4)2 = Ca + CuPO4 =>
2 Cu + Ca3(PO4)2 = 3 Ca + 2 CuPO4
B2O3 + HNO3 = B(NO3)3 + H2O =>
B2O3 + 6 HNO3 = 2 B(NO3)3 + 3 H2O
HCl + NaOH = NaCl + H2O =>
HCl + NaOH = NaCl + H2O
Fe2O3 + C + Cl2 = FeCl3 + CO =>
Fe2O3 + 3 C + 3 Cl2 = 2 FeCl3 + 3 CO
NiCl2 + Na4OH = NiOH + Na4Cl2 =>
NiCl2 + Na4OH = NiOH + Na4Cl2
PbS + HNO{3+} = Pb(NO{3+})2 + NO + S + H{2+}O =>
PbS + 3 HNO{3+} = Pb(NO{3+})2 + NO + S + 3 H{2+}O
XeO4 + Mg = Xe + MgO =>
XeO4 + 4 Mg = Xe + 4 MgO
KBr + I2 = KI2 + Br2 =>
2 KBr + 2 I2 = 2 KI2 + Br2
Sn(CO3)2 + K = K2CO3 + Sn =>
Sn(CO3)2 + 4 K = 2 K2CO3 + Sn
C8H9NO + HCl + CuCl2 + H2O = C16H21N2O3Cl3Cu =>
2 C8H9NO + HCl + CuCl2 + H2O = C16H21N2O3Cl3Cu
BaCO3 + NHO3 = H2CO3 + Ba(NO3)2 =>
BaCO3 + 2 NHO3 = H2CO3 + Ba(NO3)2
Hg + CuCl2 = HgCl + Cu =>
2 Hg + CuCl2 = 2 HgCl + Cu
Al(OH)3 + H2SO4 = Al2(SO4)3 + H2O =>
2 Al(OH)3 + 3 H2SO4 = Al2(SO4)3 + 6 H2O
Cu(OH)2CuCO3(s) = CuO(s) + CO2(g) + H2O(g) =>
Cu(OH)2CuCO3(s) = 2 CuO(s) + CO2(g) + H2O(g)
K(c) + H2O(l) = KOH(aq) + H2(g) =>
2 K(c) + 2 H2O(l) = 2 KOH(aq) + H2(g)
[H3O]Cu[ClO4]3[H2O]5 = Cu(OH)2 + H2O + HClO4 =>
[H3O]Cu[ClO4]3[H2O]5 = Cu(OH)2 + 4 H2O + 3 HClO4
CuNO3 + NH4OH = CuOH + NH4NO3 =>
CuNO3 + NH4OH = CuOH + NH4NO3
C5H11Cl + NaHCO3 = C5H11OH + NaCl + CO2 =>
C5H11Cl + NaHCO3 = C5H11OH + NaCl + CO2
K + NO3 = KNO3 =>
K + NO3 = KNO3
C3H4O3 + H2O = CO2 + H =>
C3H4O3 + 3 H2O = 3 CO2 + 10 H
Cr2O7{-2} + Hg + H2SO4 + H{+} = Hg2SO4 + Cr{+3} + H2O =>
Cr2O7{-2} + 6 Hg + 3 H2SO4 + 8 H{+} = 3 Hg2SO4 + 2 Cr{+3} + 7 H2O
HOCl + C = H2O + CO2 + Cl2 =>
4 HOCl + C = 2 H2O + CO2 + 2 Cl2
CH3CHCHCH2CH3 + KMnO4 + KOH = CH3CH2COOKCH3COOK + K2MnO4 + H2O =>
CH3CHCHCH2CH3 + 8 KMnO4 + 10 KOH = CH3CH2COOKCH3COOK + 8 K2MnO4 + 6 H2O
C5H5MgBr + FeCl3 = C10H10Fe + C10H8 + MgBr2 + MgCl2 + HCl =>
10 C5H5MgBr + 4 FeCl3 = 4 C10H10Fe + C10H8 + 5 MgBr2 + 5 MgCl2 + 2 HCl
H2S + HNO3 = H2SO4 + NO2 + H2O =>
H2S + 8 HNO3 = H2SO4 + 8 NO2 + 4 H2O
SO2 + H2O + CUSO4 = CU + H2SO4 =>
SO2 + 2 H2O + CUSO4 = CU + 2 H2SO4
KF + HCl = HF + KCl =>
KF + HCl = HF + KCl
NaCl(s) + SO2(g) + H2O(l) + O2(g) = Na2SO4(s) + HCl(l) =>
4 NaCl(s) + 2 SO2(g) + 2 H2O(l) + O2(g) = 2 Na2SO4(s) + 4 HCl(l)
HNO3 + Ba(OH)2 = H2O + Ba(NO3)2 =>
2 HNO3 + Ba(OH)2 = 2 H2O + Ba(NO3)2
C4H10 + Br = C4H9Br + H =>
C4H10 + Br = C4H9Br + H
HBr = H2 + Br2 =>
2 HBr = H2 + Br2
Equilibrar la ecuación de cualquier reacción química.
Ecuaciones balanceadas el día anterior |
Ecuaciones balanceadas en10/26/24
Ecuaciones balanceadas en11/25/23
Deje su comentario acerca de su experiencia utlizando el balanceador de ecuaciones quìmicas.