Ecuaciones balanceadas el día anterior |
Ba3 + 2 H3AsO4 = 3 H2 + Ba3(AsO4)2
Cr(NO3)3 + Na2CO3 = NaNO3 + Cr2(CO3)3 =>
2 Cr(NO3)3 + 3 Na2CO3 = 6 NaNO3 + Cr2(CO3)3
CaCO3 + Fe = Ca + FeO + CO2 =>
CaCO3 + Fe = Ca + FeO + CO2
HCl + BaCrO4 = Ba2Cl + CrCl + Cl + H2O =>
16 HCl + 2 BaCrO4 = Ba2Cl + 2 CrCl + 13 Cl + 8 H2O
KOH + NaNO3 = NaOH + KNO3(s) =>
KOH + NaNO3 = NaOH + KNO3(s)
NO4Cl + HgCH3COO = NO4CH3COO + HgCl =>
NO4Cl + HgCH3COO = NO4CH3COO + HgCl
FeCr2O4(s) + K2CO3(aq) + O2(g) = Fe2O3(s) + K2CrO4(aq) + CO2 =>
4 FeCr2O4(s) + 8 K2CO3(aq) + 7 O2(g) = 2 Fe2O3(s) + 8 K2CrO4(aq) + 8 CO2
Fe + O2 = Fe3O4 =>
3 Fe + 2 O2 = Fe3O4
CuS + H2O2 + HCl = CuCl2 + SO2 + H2O =>
CuS + 3 H2O2 + 2 HCl = CuCl2 + SO2 + 4 H2O
Cu2S + Ce{4+} + O{2-} = Cu{2+} + SO4{2-} + Ce{3+} =>
Cu2S + 10 Ce{4+} + 4 O{2-} = 2 Cu{2+} + SO4{2-} + 10 Ce{3+}
Cd + KCN + O2 + H2O = K2Cd(CN)4 + KOH =>
2 Cd + 8 KCN + O2 + 2 H2O = 2 K2Cd(CN)4 + 4 KOH
CaCO3 + Fe = Ca + FeO + CO2 =>
CaCO3 + Fe = Ca + FeO + CO2
H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O
H2O + NaHCO3 = NaOH + H2CO3 =>
H2O + NaHCO3 = NaOH + H2CO3
CH3CHO + O3 = CO2 + H2O =>
3 CH3CHO + 5 O3 = 6 CO2 + 6 H2O
(NH2)2CO = C3H6N6 + NH3 + CO2 =>
6(NH2)2CO = C3H6N6 + 6 NH3 + 3 CO2
CrI2 + K2CO3 = CrCO3 + KI =>
CrI2 + K2CO3 = CrCO3 + 2 KI
Ho + H2O = Ho(OH)3 + H2 =>
2 Ho + 6 H2O = 2 Ho(OH)3 + 3 H2
H2O2 = H2O + O2 =>
2 H2O2 = 2 H2O + O2
Bi(NO3)3 + Na2Sn(OH)3 + NaOH = Bi + NaSn(OH)6 + NaNO3 =>
4 Bi(NO3)3 + 3 Na2Sn(OH)3 + 9 NaOH = 4 Bi + 3 NaSn(OH)6 + 12 NaNO3
Cd + KCN + O2 + H2O = K2Cd(CN)4 + KOH =>
2 Cd + 8 KCN + O2 + 2 H2O = 2 K2Cd(CN)4 + 4 KOH
CaH2 + TiO2 = Ca(OH)2 + Ti =>
CaH2 + TiO2 = Ca(OH)2 + Ti
SOCl2 + C10H18O4 = C10H16O2Cl2 + HCl + SO2 =>
2 SOCl2 + C10H18O4 = C10H16O2Cl2 + 2 HCl + 2 SO2
NO4Cl + HgCH3COO = NO4CH3COO + HgCl =>
NO4Cl + HgCH3COO = NO4CH3COO + HgCl
ClO + H{+} + e = Cl + HO =>
ClO + H{+} + e = Cl + HO
HOCH2CH2OH + KBr + H2SO4 = BrCH2CH2OH + KHSO4 + H2O =>
HOCH2CH2OH + KBr + H2SO4 = BrCH2CH2OH + KHSO4 + H2O
CaCO3 + Fe = Ca + FeO + CO2 =>
CaCO3 + Fe = Ca + FeO + CO2
Pb(No3)2(aq) + K2CrO4(aq) = PbCrO4(s) + KNo3(aq) =>
Pb(No3)2(aq) + K2CrO4(aq) = PbCrO4(s) + 2 KNo3(aq)
NH2OH + KNO2 = KOH + NH2NO2 =>
NH2OH + KNO2 = KOH + NH2NO2
HCl + BaCrO4 = Ba2Cl + CrCl + Cl + H2O =>
16 HCl + 2 BaCrO4 = Ba2Cl + 2 CrCl + 13 Cl + 8 H2O
NO4Cl + HgCH3COO = NO4CH3COO + HgCl =>
NO4Cl + HgCH3COO = NO4CH3COO + HgCl
Cd + KCN + O2 + H2O = K2Cd(CN)4 + KOH =>
2 Cd + 8 KCN + O2 + 2 H2O = 2 K2Cd(CN)4 + 4 KOH
MgSO4 + AgBr = Ag2SO4 + MgBr2 =>
MgSO4 + 2 AgBr = Ag2SO4 + MgBr2
Ca(NO3)2 + MgBr2 = CaBr2 + Mg(NO3)2 =>
Ca(NO3)2 + MgBr2 = CaBr2 + Mg(NO3)2
CaCO3 + Fe = Ca + FeO + CO2 =>
CaCO3 + Fe = Ca + FeO + CO2
PbO2 + Sb + KOH = KSbO2 + PbO + H2O =>
3 PbO2 + 2 Sb + 2 KOH = 2 KSbO2 + 3 PbO + H2O
NH2OH + KNO2 = KOH + NH2NO2 =>
NH2OH + KNO2 = KOH + NH2NO2
HCl + BaCrO4 = Ba2Cl + CrCl + Cl + H2O =>
16 HCl + 2 BaCrO4 = Ba2Cl + 2 CrCl + 13 Cl + 8 H2O
CaH2 + TiO2 = Ca(OH)2 + Ti =>
CaH2 + TiO2 = Ca(OH)2 + Ti
KOH + NaNO3 = NaOH + KNO3(s) =>
KOH + NaNO3 = NaOH + KNO3(s)
C6H5CH3 + KMnO4 + H2SO4 = C6H5COOH + MnSO4 + K2SO4 + H2O =>
5 C6H5CH3 + 6 KMnO4 + 9 H2SO4 = 5 C6H5COOH + 6 MnSO4 + 3 K2SO4 + 14 H2O
K3PO4(ag) + MgCl2(ag) = Mg(PO4)(s) + K3Cl2(ag) =>
K3PO4(ag) + MgCl2(ag) = Mg(PO4)(s) + K3Cl2(ag)
C6H11Cl = C6H10 + HCl =>
C6H11Cl = C6H10 + HCl
KHS(aq) + HCl(aq) = KCl(aq) + H2S(g) =>
KHS(aq) + HCl(aq) = KCl(aq) + H2S(g)
KOH + NaNO3 = NaOH + KNO3(s) =>
KOH + NaNO3 = NaOH + KNO3(s)
HCl + BaCrO4 = Ba2Cl + CrCl + Cl + H2O =>
16 HCl + 2 BaCrO4 = Ba2Cl + 2 CrCl + 13 Cl + 8 H2O
HNO3 + Ba(OH)2 = Ba(NO3)2 + H2O =>
2 HNO3 + Ba(OH)2 = Ba(NO3)2 + 2 H2O
Cr(NO3)3 + Na2CO3 = NaNO3 + Cr2(CO3)3 =>
2 Cr(NO3)3 + 3 Na2CO3 = 6 NaNO3 + Cr2(CO3)3
Ca + H2O = Ca(OH)2 + H3 =>
3 Ca + 6 H2O = 3 Ca(OH)2 + 2 H3
NO4Cl + HgCH3COO = NO4CH3COO + HgCl =>
NO4Cl + HgCH3COO = NO4CH3COO + HgCl
Equilibrar la ecuación de cualquier reacción química.
Ecuaciones balanceadas el día anterior |
Ecuaciones balanceadas en12/11/24
Ecuaciones balanceadas en01/10/24
Deje su comentario acerca de su experiencia utlizando el balanceador de ecuaciones quìmicas.